There are ten boys B 1 , B 2 , … . , B 10 and five girls G 1 , G 2 , … . G 5 in a class. Then the number of ways of forming a group consisting of three boys and three girls, if both B 1 and B 2 together should not be the members of a group, is _____.

Question

There are ten boys B 1 , B 2 , … . , B 10 and five girls G 1 , G 2 , … . G 5 in a class. Then the number of ways of forming a group consisting of three boys and three girls, if both B 1 and B 2 together should not be the members of a group, is _____.,

MARKS App · Accepted Answer

Given, total number of boys is 10 and total number of girls is 5 So total number of selections = C 3 10 · C 3 5 = 1200 No. of selections in which B 1 & B 2 both are there in group = C 1 8 · C 3 5 = 80 Required no. of selections = 1200 - 80 = 1120

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