Join the Most Relevant JEE Main 2025 Test Series & get 99+ percentile! Join Now
Search any question & find its solution
Question: Answered & Verified by Expert
Thermodynamic standard conditions of temperature and pressure are
ChemistryThermodynamics (C)COMEDKCOMEDK 2020
Options:
  • A $0^{\circ} \mathrm{C}$ and $1 \mathrm{~atm}$
  • B $273 \mathrm{~K}$ and $101.3 \mathrm{kPa}$
  • C $298 \mathrm{~K}$ and $1 \mathrm{~atm}$
  • D $0^{\circ} \mathrm{C}$ and $101.3 \mathrm{kPa}$
Solution:
2201 Upvotes Verified Answer
The correct answer is: $0^{\circ} \mathrm{C}$ and $1 \mathrm{~atm}$
Thermodynamic standard condition of temperature and pressure is $273 \mathrm{~K}\left(0^{2} \mathrm{C}\right)$ and $1 \mathrm{~atm}(760 \mathrm{~mm} \mathrm{Hg})$.

Looking for more such questions to practice?

Download the MARKS App - The ultimate prep app for IIT JEE & NEET with chapter-wise PYQs, revision notes, formula sheets, custom tests & much more.