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Question: Answered & Verified by Expert
This time period of a particle undergoing SHM is 16 s. It starts motion from the mean position. After 2 s, its velocity is 0.4 m s-1. The amplitude is
PhysicsOscillationsNEET
Options:
  • A 1.44 m
     
     
  • B 0.72 m
     
     
  • C 2.88 m
     
  • D 0.36 m
     
Solution:
2018 Upvotes Verified Answer
The correct answer is: 1.44 m
 
 
Velocity, v=rωcosωt;

0.4=r×2π16cos2π16×2=r×2π16×12

or r=0.4×16×22π=3.22π=1.44 m

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