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Three capacitors $\mathrm{C}_{1}=1 \mu \mathrm{F}, \mathrm{C}_{2}=2 \mu \mathrm{F}$ and $\mathrm{C}_{3}=3$
$\mu \mathrm{F}$ are connected as shown in figure, then the equivalent capacitance between points A and $\mathrm{B}$ is
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$\mu \mathrm{F}$ are connected as shown in figure, then the equivalent capacitance between points A and $\mathrm{B}$ is
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Verified Answer
The correct answer is:
$6 \mu \mathrm{F}$
$C_{\mathrm{eq}}=(1+2+3) \mu \mathrm{F}=6 \mu \mathrm{F}$
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