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Three capacitors each of capacity $4 \mu \mathrm{F}$ are to be connected in such a way that the effective capacitance is $6 \mu \mathrm{F}$. This can be done by:
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Verified Answer
The correct answer is:
connecting two in series and one in parallel
$$
\begin{aligned}
& \mathrm{C}_{\mathrm{AB}}=(2+4) \mu \mathrm{F} \\
& =6 \mu \mathrm{F}
\end{aligned}
$$
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