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Question: Answered & Verified by Expert
Three containers C1,C2 and C3 have water at different temperatures. The table below shows the final temperature T when different amounts of water (given in liters) are taken from each container and mixed (assume no loss of heat during the process)




































C1 C2 C3 T
1l 2l -- 60oC
-- 1l 2l 30oC
2l -- 1l 60oC
1l 1l 1l θ



The value of θ (in oC to the nearest integer) is___________
PhysicsThermal Properties of MatterJEE MainJEE Main 2020 (08 Jan Shift 2)
Solution:
2567 Upvotes Verified Answer
The correct answer is: 50

Let θ1θ2 and θ3 be the temperatures of water in three containers.

1θ1+2θ2+0θ3=1+260
θ1+2θ2=180 …. (1)
0×θ1+1×θ2+2×θ3=1+230
θ2+2θ3=90 …… (2)
2×θ1+0×θ2+1×θ3=2+160
2θ1+θ3=180 …. (3)
and θ1+θ2+θ3=1+1+1θ
from (1)+(2)+(3)
3θ1+3θ2+3θ3=450θ1+θ2+θ3=150
from (4) equation 150=3θθ=50 °C

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