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Three dice are thrown. What is the probability that the same number will appear on each of them?
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The correct answer is:
$\frac{1}{36}$
Total no. of case $=6^{3}=216$ Favourable cases $=\{(1,1,1),(2,2,2),(3,3,3),(4,4,4),$,
$(5,5,5),(6,6,6)\}$
Probability $=\frac{6}{216}=\frac{1}{36}$
$(5,5,5),(6,6,6)\}$
Probability $=\frac{6}{216}=\frac{1}{36}$
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