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Three digital numbers are formed using the digits $0,2,4,6,8$. A number is chosen at random out of these numbers. What is the probability that the number has the same digits?
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The correct answer is:
$1 / 25$
Given digits are $0,2,4,6,8$. Total number of cases $=4 \times 4 \times 4$
(\becauseWe have 4 choices for each number)
Required probability $=\frac{4}{64}=\frac{1}{16}$
(\becauseWe have 4 choices for each number)
Required probability $=\frac{4}{64}=\frac{1}{16}$
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