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Three digits are chosen at random from $1,2,3,4,5,6,7,8$ and 9 without repeating any digit. What is the probability that the product is odd ?
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The correct answer is:
$\frac{5}{42}$
Total no. of 3 -digit numbers $=9 \times 8 \times 7=504$ For product to be odd, we have to choose only from odd numbers. $\therefore$ Total no. of 3 -digit no. whose product are odd $=5 \times 4 \times 3=60$
$\therefore$ Required probability $=\frac{60}{504}=\frac{5}{42}$
$\therefore$ Required probability $=\frac{60}{504}=\frac{5}{42}$
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