Search any question & find its solution
Question:
Answered & Verified by Expert
Three perfect gases at absolute temperatures $T_1, T_2$ and $T_3$ are mixed. The masses of molecules are $m_1$, $m_2$ and $m_3$ and the number of molecules are $n_1, n_2$ and $n_3$ respectively. Assuming no loss of energy, the final temperature of the mixture is :
Options:
Solution:
1873 Upvotes
Verified Answer
The correct answer is:
$\frac{n_1 T_1+n_2 T_2+n_3 T_3}{n_1+n_2+n_3}$
$\frac{n_1 T_1+n_2 T_2+n_3 T_3}{n_1+n_2+n_3}$
Data $\Rightarrow n, k, t_1+n_2 k T_2+n_3 k T_3=\left(n_1+n_2+n_3\right) k T$
$\therefore T=\frac{n_1 T_1+n_2 T_2+n_3 T_3}{n_1+n_2+n_3}$
$\therefore T=\frac{n_1 T_1+n_2 T_2+n_3 T_3}{n_1+n_2+n_3}$
Looking for more such questions to practice?
Download the MARKS App - The ultimate prep app for IIT JEE & NEET with chapter-wise PYQs, revision notes, formula sheets, custom tests & much more.