Search any question & find its solution
Question:
Answered & Verified by Expert
Three points charges $+q,-2 q$ and $+q$ are placed at points $(x=0, y=a, z=0),(x=0, y=0, z=0)$ and $\quad(x=a, y=0, z=0)$, respectively. The magnitude and direction of the electric dipole moment vector of this charge assembly are
Options:
Solution:
1400 Upvotes
Verified Answer
The correct answer is:
$\sqrt{2} q a$ along the line joining points
$(x=0, y=0, z=0) \text { and }(x=a, y=a, z=0)$
$(x=0, y=0, z=0) \text { and }(x=a, y=a, z=0)$
$O$ is the origin at which $-2 q$ charge is placed. The system is equivalent to two dipoles along $x$ and $y$-directions respectively. The dipole moments of two dipoles are shown in figure.
The resultant dipole moment will be directed along $O P$ where $P=(a, a, 0)$. The magnitude of resultant dipole moment is
$p^{\prime}=\sqrt{p^2+p^2}=\sqrt{(q a)^2+(q a)^2}=\sqrt{2} q a$
The resultant dipole moment will be directed along $O P$ where $P=(a, a, 0)$. The magnitude of resultant dipole moment is
$p^{\prime}=\sqrt{p^2+p^2}=\sqrt{(q a)^2+(q a)^2}=\sqrt{2} q a$
Looking for more such questions to practice?
Download the MARKS App - The ultimate prep app for IIT JEE & NEET with chapter-wise PYQs, revision notes, formula sheets, custom tests & much more.