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Three rods of identical cross-sectional area and made from the same metal form the sides of an isosceles triangle right angled at . The points and are maintained at temperatures and , respectively, in the steady-state. Assuming that only heat conduction takes place, the temperature of the point is

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The correct answer is:
As TB > TA, heat flows from B to A through both paths BA and BCA.
Rate of heat flow in BC = Rate of heat flow in CA
Solving this, we get

Rate of heat flow in BC = Rate of heat flow in CA
Solving this, we get

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