Join the Most Relevant JEE Main 2025 Test Series & get 99+ percentile! Join Now
Search any question & find its solution
Question: Answered & Verified by Expert
Three rods of same dimensions have thermal conductivities 3K, 2K,and K , with their ends at 100 °C,50 °C and 0 °C respectively. They are arranged as shown in the diagram. The temperature of the junction J in steady-state is
 
                
PhysicsCurrent ElectricityNEET
Options:
  • A 2003°C
  • B 1003°C
  • C 75 °C
  • D 60 °C
Solution:
1831 Upvotes Verified Answer
The correct answer is: 2003°C
Let T = temperature of the junction J
L = length and A = area of each rod
Heat conducted in first rod = heat conducted by second rod + heat conducted by third rod
3KA100-TL=2KAT-50L+AKT-0L

3100-T=2T-50+T

      400 = 6T

          T =2003°C

Looking for more such questions to practice?

Download the MARKS App - The ultimate prep app for IIT JEE & NEET with chapter-wise PYQs, revision notes, formula sheets, custom tests & much more.