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Time required to deposit one millimole of aluminium metal by the passage of 9.65 amperes through aqueous solution of aluminium ion is
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$10 \mathrm{~s}$
$ \mathrm{Al}^{3+}+3 e^{-} \rightarrow \mathrm{Al}$
For deposition of $1 \mathrm{~g}$ equivalent $\equiv 96500 \mathrm{C}$
For deposition of 1 millimole $\equiv 96.500 \mathrm{C}$
As $Q=I t \Rightarrow t=\frac{Q}{I}=\frac{96.5}{9.65}=10 \mathrm{~s}$
For deposition of $1 \mathrm{~g}$ equivalent $\equiv 96500 \mathrm{C}$
For deposition of 1 millimole $\equiv 96.500 \mathrm{C}$
As $Q=I t \Rightarrow t=\frac{Q}{I}=\frac{96.5}{9.65}=10 \mathrm{~s}$
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