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To get an output $y=0$ from the circuit shown in the figure, the input $C$ must be
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As we know, output of OR gate $\mathrm{Y}=\mathrm{A}+\mathrm{B}$
Output of AND gate
$\begin{aligned}
& Y^{\prime}=Y . C \\
\Rightarrow & Y^{\prime}=(A+B) \cdot C
\end{aligned}$
If $\mathrm{C}=0$ irrespective of $\mathrm{A}$ and $\mathrm{B}$, then output $Y$ must be zero.
Output of AND gate
$\begin{aligned}
& Y^{\prime}=Y . C \\
\Rightarrow & Y^{\prime}=(A+B) \cdot C
\end{aligned}$
If $\mathrm{C}=0$ irrespective of $\mathrm{A}$ and $\mathrm{B}$, then output $Y$ must be zero.
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