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To prepare a pure sample of n-hexane using sodium metal as one reactant, the other reactant will be
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n-propyl bromide
According to wurtz reaction.
$2 \mathrm{CH}_3 \mathrm{CH}_2 \mathrm{CH}_2 \mathrm{Br}+2 \mathrm{Na} \xrightarrow{\text { ether }}$ $\mathrm{CH}_3\left(\mathrm{CH}_2\right)_4 \mathrm{CH}_3+2 \mathrm{NaBr}$
$2 \mathrm{CH}_3 \mathrm{CH}_2 \mathrm{CH}_2 \mathrm{Br}+2 \mathrm{Na} \xrightarrow{\text { ether }}$ $\mathrm{CH}_3\left(\mathrm{CH}_2\right)_4 \mathrm{CH}_3+2 \mathrm{NaBr}$
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