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Total number of atoms represented by the compound $\mathrm{CuSO}_4 \cdot 5 \mathrm{H}_2 \mathrm{O}$ is
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$21$
Total number of atoms in $\mathrm{CuSO} 4 \cdot 5 \mathrm{H} 2 \mathrm{O}=1+1+4+5 \times 3=21$
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