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Total number of four digit odd numbers that can be formed using $0,1,2,3,5,7$ are
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Verified Answer
The correct answer is:
$720$
we have the number \(0,1,2,3,5,7\)
Now the digit should be odd and hence last digit should be filled with an odd number
\(\Rightarrow\) Number of way to filled last number \(=4\) (i.e. \(1,3,5,7\) )
\(\Rightarrow\) Number of way to filled third digit \(=6\) (i.e. o,1, 2, 3, 5, 7)
\(\Rightarrow\) Number of way to filled second digit \(=6\) (i.e. o,1, 2, 3, 5, 7)
\(\Rightarrow\) Number of way to filled first digit \(=5\) (i.e.1, \(2,3,5,7\) )
\(\Rightarrow\) Total 4 digit number \(=4 \times 6 \times 6 \times 5\)
\(=720\)
Now the digit should be odd and hence last digit should be filled with an odd number
\(\Rightarrow\) Number of way to filled last number \(=4\) (i.e. \(1,3,5,7\) )
\(\Rightarrow\) Number of way to filled third digit \(=6\) (i.e. o,1, 2, 3, 5, 7)
\(\Rightarrow\) Number of way to filled second digit \(=6\) (i.e. o,1, 2, 3, 5, 7)
\(\Rightarrow\) Number of way to filled first digit \(=5\) (i.e.1, \(2,3,5,7\) )
\(\Rightarrow\) Total 4 digit number \(=4 \times 6 \times 6 \times 5\)
\(=720\)
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