Join the Most Relevant JEE Main 2025 Test Series & get 99+ percentile! Join Now
Search any question & find its solution
Question: Answered & Verified by Expert
Total number of relatively more stable isomer(s) possible for octahedral complex Cuen2SCN2 will be____
ChemistryCoordination CompoundsJEE MainJEE Main 2022 (28 Jul Shift 1)
Solution:
2123 Upvotes Verified Answer
The correct answer is: 3

This octahedral complex is of M(AA)2b2 type structure in which AA is bidentate ligand and b is monodentate ligand. This can exist in two geometrical isomeric form cis and trans. Out of which trans form is relatively more stable isomer. Now due to ambidentate ligand SCN- it can also shows linkage isomersim.

Cuen2SCN2

So, relatively more stable trans isomers will have three possible isomers.

Looking for more such questions to practice?

Download the MARKS App - The ultimate prep app for IIT JEE & NEET with chapter-wise PYQs, revision notes, formula sheets, custom tests & much more.