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Two balls of masses $m_1$ and $m_2$ are separated from each other by a powder charge placed between them. The whole system is at rest on the ground. Suddenly the powder charge explodes and masses are pushed apart. The mass $m_1$ travels a distance $s_1$ and stops. If the coefficients of friction between the balls and ground are same, the mass $m_2$ stops after travelling the distance
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Verified Answer
The correct answer is:
$s_2=\frac{m_1^2}{m_2^2} s_1$
We know that in the given condition $s \propto \frac{1}{m^2}$
$\therefore \frac{s_2}{s_1}=\left(\frac{m_1}{m_2}\right)^2 \Rightarrow s_2=\left(\frac{m_1}{m_2}\right)^2 \times s_1$
$\therefore \frac{s_2}{s_1}=\left(\frac{m_1}{m_2}\right)^2 \Rightarrow s_2=\left(\frac{m_1}{m_2}\right)^2 \times s_1$
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