Two blocks of masses 2 k g and 1 k g respectively are tied to the ends of a string which passes over a light frictionless pulley. The masses are held at rest at the same horizontal level and then released. The distance traversed by centre of mass in 2 s is g = 10 m s - 2

Question

Two blocks of masses 2 k g and 1 k g respectively are tied to the ends of a string which passes over a light frictionless pulley. The masses are held at rest at the same horizontal level and then released. The distance traversed by centre of mass in 2 s is g = 10 m s - 2, 1.42 m, 2.22 m, 3.12 m, 3.33 m

MARKS App · Accepted Answer

Acceleration of each block is, Here acceleration of center of mass is, a = m 2 - m 1 m 2 - m 1 g a = 2 - 1 2 + 1 g ⁡ = 10 3 m s - 2 a c m = m 2 a + m 1 - a m 2 + m 1 a c m = 2 - 1 2 + 1 a ⁡ = 10 9 m s - 2 Displacement of center of mass is, S C M = 1 2 a C M t 2 = 1 2 10 9 2 2 ⇒ S C M = 2.22 m

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