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Question: Answered & Verified by Expert
Two blocks of masses M=3 kg and m=2 kg, are in contact on a horizontal table. A constant horizontal force F=5 N is applied to block M as shown. There is a constant frictional force of 2 N between the table and the block m but no frictional force between the table and the first block M, then the acceleration of the two blocks is

PhysicsLaws of MotionNEET
Options:
  • A 0.4 m s-2 
  • B 0.6 m s-2
  • C 0.8 m s-2
  • D m s-2
Solution:
1164 Upvotes Verified Answer
The correct answer is: 0.6 m s-2
Net force = total mass × accelaration

a=F-fM+m

a=5-23+2

a=0.6 m s-2 

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