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Question: Answered & Verified by Expert
Two bodies of masses m1 and m2 are infinitely at rest at an infinite distance apart. They are then allowed to move towards each other under mutual gravitational attraction. The relative velocity of approach at a separation r between them is
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Options:
  • A 2Gm1+m2r12
  • B 2Grm1m212
  • C 2Gm1-m2r12
  • D r2Gm1 m212
Solution:
2709 Upvotes Verified Answer
The correct answer is: 2Gm1+m2r12
Change in P.E = Change in K.E

12μv2=Gm1m2r 

Where, μ is reduces mass

μ=m1m2m1+m2

12m1m2m1+m2 v2=Gm1m2r

v=2Grm1+m2

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