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Question: Answered & Verified by Expert
Two boys of masses 10 kg and 8 kg are moving along a vertical rope, the former climbing up with the acceleration of 2 m s-2 while the later coming down with a uniform velocity of 2 m s-1. Then tension in the rope at the fixed support is  (Take g = 10 m s-2 )
PhysicsLaws of MotionNEET
Options:
  • A 200 N
     
  • B 120 N
     
  • C 180 N
     
  • D 160 N
     
Solution:
2099 Upvotes Verified Answer
The correct answer is: 200 N
 
Since, m2 moves with constant velocity.

f2=m2g

f2=8 ×10=80 N

Since, block m1 moves with acceleration




a=2 m s-2 in the upward direction.

f1-m1g=m1a

f1=m1g+m1a

=10 ×10+10×2

=120 N

For equilibrium of rope,




T=f1+f2

=120+80 N

=200 N

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