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Two capacitors each of capacity $2 \mu F$ are connected in parallel. This system is connected in series with a third capacitor of $12 \mu F$ capacity. The equivalent capacity of the system will be
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The correct answer is:
$3 \mu F$
$\Rightarrow C_{A B}=\frac{4 \times 12}{4+12}=3 \mu F$
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