Search any question & find its solution
Question:
Answered & Verified by Expert
Two capacitors of capacities $\mathrm{C}$ and $2 \mathrm{C}$ are connected in parallel and then connected in series with a third capacitor of capacity $3 \mathrm{C}$. The combination is charged with $\mathrm{V}$ volt. The charge on capacitor of capacity $\mathrm{C}$ is
Options:
Solution:
1650 Upvotes
Verified Answer
The correct answer is:
$\frac{1}{2} \mathrm{CV}$
In parallel combination, the potential difference across each individual capacitor is the same as the potenital difference across the combination.
So, potential difference across capacitor of capacity $\mathrm{C}$ is $\frac{V}{2}$.
Charge on capacitor, $\mathrm{C}=\frac{Q}{V}$
$\therefore$ Charge on capacitor of capacity $\mathrm{C}=\frac{C V}{2}$
So, potential difference across capacitor of capacity $\mathrm{C}$ is $\frac{V}{2}$.
Charge on capacitor, $\mathrm{C}=\frac{Q}{V}$
$\therefore$ Charge on capacitor of capacity $\mathrm{C}=\frac{C V}{2}$
Looking for more such questions to practice?
Download the MARKS App - The ultimate prep app for IIT JEE & NEET with chapter-wise PYQs, revision notes, formula sheets, custom tests & much more.