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Two charged spheres separated by a distance ' $d$ ' exert some force on each other. If they are immersed in a liquid of dielectric constant 2 , then what is the force exerted, if all other conditions are same?
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The correct answer is:
$F / 2$
Given: Distance between two charges $=d$ and dielectric constant $(k)=2$. Force between two charged spheres $(F)=\frac{1}{4 \pi \varepsilon_0} \times \frac{q_1 q_2}{r_2}$, where $\varepsilon_0$ is permitivity of free space. Force for a medium with dielectric constant $k$,
$F^{\prime}=\frac{1}{k} \times \frac{1}{4 \pi \varepsilon_0} \times \frac{q_1 q_2}{r^2}=\frac{F}{k}=\frac{F}{2}$
$F^{\prime}=\frac{1}{k} \times \frac{1}{4 \pi \varepsilon_0} \times \frac{q_1 q_2}{r^2}=\frac{F}{k}=\frac{F}{2}$
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