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Two circuits (a) and (b) have charged capacitors of capacitance C, 2C and 3C with open switches. Charges on each of the capacitor are as shown in the figures. On closing the switches


Circuit (a) Circuit (b)
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Circuit (a) Circuit (b)
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The correct answer is:
Charges flow from $R$ to $L$ in (a) and from $L$ to $R$ in (b)
Charges flow from $R$ to $L$ in (a) and from $L$ to $R$ in (b)
Charge (or current) always flows from higher potential to lower potential.
Potential $=\frac{\text { Charge }}{\text { Capacitance }}$
Potential $=\frac{\text { Charge }}{\text { Capacitance }}$
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