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Question: Answered & Verified by Expert
Two circular plates of radius $5 \mathrm{~cm}$ each, have a 0.01 mm thick water film between them. Then what will be the force required to separate these plate (S.T. of water $=73$ dyne/cm)?
PhysicsMechanical Properties of FluidsBITSATBITSAT 2010
Options:
  • A $125 \mathrm{~N}$
  • B $95 \mathrm{~N}$
  • C $115 \mathrm{~N}$
  • D $105 \mathrm{~N}$
Solution:
2063 Upvotes Verified Answer
The correct answer is: $115 \mathrm{~N}$
$\begin{aligned} \mathrm{F}=& \frac{2 \mathrm{AT}}{\mathrm{d}}=\frac{2 \times \pi \times(0.05)^{2} \times 73 \times 10^{-3}}{0.01 \times 10^{-3}} \\=& 36.5 \pi \approx 115 \text { newton } \end{aligned}$

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