Join the Most Relevant JEE Main 2025 Test Series & get 99+ percentile! Join Now
Search any question & find its solution
Question: Answered & Verified by Expert
Two coherent beams of wavelength 5000 A reaching a point would individually produce intensities 1.44 and 4.00 units. If they reach there together, the intensity is 10.24 units. Calculate the lowest phase difference with which the beams reach that point.
PhysicsWave OpticsNEET
Options:
  • A zero
  • B π4
  • C π2
  • D π
Solution:
2954 Upvotes Verified Answer
The correct answer is: zero
Resultant intensity at the point where the two coherent beam reach together is given by

I=I1+I2+2I1 I2cosϕ

   10.24=1.44+4.00+2 1.44×4.00cosϕ

    10.24=5.44+4.8cosϕ

 cosϕ=10.24-5.444.8=1

   ϕ=0

Looking for more such questions to practice?

Download the MARKS App - The ultimate prep app for IIT JEE & NEET with chapter-wise PYQs, revision notes, formula sheets, custom tests & much more.