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Two coherent sources of intensities $\mathrm{l}_{1}$ and $\mathrm{I}_{2}$ produce an interference pattern on screen. The maximum intensity in the interference pattern is
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Verified Answer
The correct answer is:
$\left[\sqrt{\mathrm{I}_{1}}+\sqrt{\mathrm{I}_{2}}\right]^{2}$
Intensity is proportional to square of the amplitude.
$\mathrm{I} \propto \mathrm{a}^{2}$
$\therefore \sqrt{\mathrm{I}} \propto \mathrm{a}$
Maximum intensity is produced when the two amplitudes get added (phase difference is $2 n \pi$ ).
$\therefore \mathrm{I}_{\max } \propto\left(\mathrm{a}_{1}+\mathrm{a}_{2}\right)^{2} \quad$ or $\mathrm{I}_{\max } \propto\left(\sqrt{\mathrm{I}}_{1}+\sqrt{\mathrm{I}}_{2}\right)^{2}$
$\mathrm{I} \propto \mathrm{a}^{2}$
$\therefore \sqrt{\mathrm{I}} \propto \mathrm{a}$
Maximum intensity is produced when the two amplitudes get added (phase difference is $2 n \pi$ ).
$\therefore \mathrm{I}_{\max } \propto\left(\mathrm{a}_{1}+\mathrm{a}_{2}\right)^{2} \quad$ or $\mathrm{I}_{\max } \propto\left(\sqrt{\mathrm{I}}_{1}+\sqrt{\mathrm{I}}_{2}\right)^{2}$
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