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Two condensers, one of capacity $C$ and the other of capacity $\frac{C}{2}$, are connected to a $V$-volt battery, as shown.
The work done in charging fully both the condensers is
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The work done in charging fully both the condensers is
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Verified Answer
The correct answer is:
$\frac{3}{4} C V^2$
The two condensers in the circuit are in parallel order, hence $C^{\prime}=C+\frac{C}{2}=\frac{3 C}{2}$
The work done in charging the equivalent capacitor is stored in the form of potential energy.
Hence, $W=U=\frac{1}{2} C^{\prime} V^2=\frac{1}{2}\left(\frac{3 C}{2}\right) V^2=\frac{3}{4} C V^2$
The work done in charging the equivalent capacitor is stored in the form of potential energy.
Hence, $W=U=\frac{1}{2} C^{\prime} V^2=\frac{1}{2}\left(\frac{3 C}{2}\right) V^2=\frac{3}{4} C V^2$
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