Join the Most Relevant JEE Main 2025 Test Series & get 99+ percentile! Join Now
Search any question & find its solution
Question: Answered & Verified by Expert
Two converging lenses of focal length $20 \mathrm{~cm}$ and $40 \mathrm{~cm}$ are placed in contact. The effective power of the combination is
PhysicsRay OpticsCOMEDKCOMEDK 2021
Options:
  • A $5.25 \mathrm{D}$
  • B $7.25 \mathrm{D}$
  • C $2.75 \mathrm{D}$
  • D $7.5 \mathrm{D}$
Solution:
1091 Upvotes Verified Answer
The correct answer is: $7.5 \mathrm{D}$
Given, $f_{1}=20 \mathrm{~cm}, f_{2}=40 \mathrm{~cm}$
Since, power $P=\frac{1}{f} \Rightarrow P_{1}=\frac{1}{f_{1}}=\frac{100}{20}=5 \mathrm{D}$ and $\quad P_{2}=\frac{1}{f_{2}}=\frac{100}{40}=25 \mathrm{D}$
Effective power, $P=P_{1}+P_{2}=5+25=7.5 \mathrm{D}$

Looking for more such questions to practice?

Download the MARKS App - The ultimate prep app for IIT JEE & NEET with chapter-wise PYQs, revision notes, formula sheets, custom tests & much more.