Two electric lamps A and B radiate the same power. Their filaments have the same dimensions and have emissivities e A and e B respectively. Their surface temperatures are T A and T B . The ratio T A T B will be equal to

Question

Two electric lamps A and B radiate the same power. Their filaments have the same dimensions and have emissivities e A and e B respectively. Their surface temperatures are T A and T B . The ratio T A T B will be equal to, ( e B e A ) 1 / 4, ( e B e A ) 1 / 2, ( e A e B ) 1 / 2, ( e A e B ) 1 / 4

MARKS App · Accepted Answer

The power radiated by a filament is P = e A σ T 4 (where e = emissivity, σ = Stefan's constant and T = surface temperature) Here, e T 4 = constant or e A T A 4 = e B T B 4

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