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Two fair dice are rolled. The probability of the sum of digits on their faces to be greater than or equal to 10 is
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Verified Answer
The correct answer is:
$\frac{1}{6}$
Total samle points, $n(S)=6 \times 6=36$
Favourable events
$$
=[(6,4),(6,5),(6,6),(5,5),(5,6),(4,6)]
$$
Total favourable events, $n(E)=6$
Required probability
$$
=\frac{n(E)}{n(S)}=\frac{6}{36}=\frac{1}{6}
$$
Favourable events
$$
=[(6,4),(6,5),(6,6),(5,5),(5,6),(4,6)]
$$
Total favourable events, $n(E)=6$
Required probability
$$
=\frac{n(E)}{n(S)}=\frac{6}{36}=\frac{1}{6}
$$
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