Two Faraday of electricity is passed through a solution of C u S O 4 . The mass of copper deposited at the cathode is: (Atomic mass of Cu = 63.5 amu)

Question

Two Faraday of electricity is passed through a solution of C u S O 4 . The mass of copper deposited at the cathode is: (Atomic mass of Cu = 63.5 amu), 127 g, 0 g, 63.5 g, 2 g

MARKS App · Accepted Answer

Cu + 2 + 2 e - → Cu 2 Faraday charge deposits 1 mol of Cu, or 2 F ≡ 2 Equivalents of Cu Mass of Cu deposited = 2 × 63 .5 2 = 63 .5 g

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