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Two fixed frictionless inclined plane making an angle $30^{\circ}$ and $60^{\circ}$ with the vertical are shown in the figure. Two block $A$ and $B$ are placed on the two planes. What is the relative vertical acceleration of $A$ with respect to $B$ ?
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The correct answer is:
$4.9 \mathrm{~ms}^{-2}$ in vertical direction
$4.9 \mathrm{~ms}^{-2}$ in vertical direction
$m g \sin \theta=m a$
$\therefore \quad a=g \sin \theta$
where $\mathrm{a}$ is along the inclined plane
$\therefore \quad$ vertical component of acceleration is $\mathrm{g} \sin ^2 \theta$
$\therefore \quad$ relative vertical acceleration of $A$ with respect to $B$ is
$\therefore \quad a=g \sin \theta$
where $\mathrm{a}$ is along the inclined plane
$\therefore \quad$ vertical component of acceleration is $\mathrm{g} \sin ^2 \theta$
$\therefore \quad$ relative vertical acceleration of $A$ with respect to $B$ is
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