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Two forces, $F_1$ and $F_2$ are acting on a body. One force is double that of the other force and the resultant is equal to the greater force. Then the angle between the two forces is
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Verified Answer
The correct answer is:
$\cos ^{-1}(-1 / 4)$
Correct option is 3. $\cos ^{-1}(-1 / 4)$
Given
$F_1=F \quad F_2=2 F$ and
$F_R=2 F$
As we know
$F_R=\sqrt{F_1^2+F_2^2+2 F_1 F_2 \cos A}$
putting the above values, we get
$-F^2=4 F \cos A$
$\cos A=\frac{-1}{4}$
$A=\cos ^{-1}\left(\frac{-1}{4}\right)$
Given
$F_1=F \quad F_2=2 F$ and
$F_R=2 F$
As we know
$F_R=\sqrt{F_1^2+F_2^2+2 F_1 F_2 \cos A}$
putting the above values, we get
$-F^2=4 F \cos A$
$\cos A=\frac{-1}{4}$
$A=\cos ^{-1}\left(\frac{-1}{4}\right)$
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