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Two gases A and B are at absolute temperatures $360 \mathrm{~K}$ and $420 \mathrm{~K}$ respectively. The ratio of average kinetic energy of the molecules of gas B to that of gas A is
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$7: 6$
The mean kinetic energy $\frac{1}{2} \mathrm{~m}<\mathrm{v}>^2$ of the gas molecule is proportional to the temperature $\mathrm{T}$.
$\frac{\mathrm{K}_{\mathrm{B}}}{\mathrm{K}_{\mathrm{A}}}=\frac{\mathrm{T}_{\mathrm{B}}}{\mathrm{T}_{\mathrm{A}}}=\frac{420}{360}=\frac{7}{6}$
$\frac{\mathrm{K}_{\mathrm{B}}}{\mathrm{K}_{\mathrm{A}}}=\frac{\mathrm{T}_{\mathrm{B}}}{\mathrm{T}_{\mathrm{A}}}=\frac{420}{360}=\frac{7}{6}$
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