Two gases A and B are released from the two ends of a tunnel of length 100 m . A travels 40 min , before meeting the gas B in the tunnel. If the molecular weight of B is 18 , what is the molecular weight of A ?

Question

Two gases A and B are released from the two ends of a tunnel of length 100 m . A travels 40 min , before meeting the gas B in the tunnel. If the molecular weight of B is 18 , what is the molecular weight of A ?, 28 . 5, 10 . 5, 8 . 5, 40 . 5

MARKS App · Accepted Answer

According to Graham's Law of Diffusion Distance travelled by B t B Distance travelled by A t a = M A 18 Here , M A = ? , M B = 18 t A = t B 100 - 40 40 = M A 18 M A = 40 . 5 g Hence, option D is correct

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