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Two glass bulbs A and B are connected by a very small tube having a stop-cock. BulbA has a volume of $100 \mathrm{~cm}^{3}$ and contained the gas while bulb B was empty. On opening stop-clock, the pressure fell down to $40 \%$. The volume of the bulb $B$ must be
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$125 \mathrm{~cm}^{3}$
$\quad \therefore \quad 100 \times p=\mathrm{V}_{2} \times \frac{40 p}{100}$ $\mathrm{~V}_{2}=250 \mathrm{cc}$ (Total volume) Volume of bul b $\mathrm{B}=250-100=150 \mathrm{cc}$
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