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Question: Answered & Verified by Expert
Two identical capacitors each of capacitance 5μF are charged to potentials 2kV and 1kV respectively. Their -ve ends are connected together. When the +ve ends are also connected together, the loss of energy of the system is
PhysicsElectrostaticsNEET
Options:
  • A 160 J
  • B Zero
  • C 5 J
  • D 1.25 J
Solution:
1253 Upvotes Verified Answer
The correct answer is: 1.25 J
Loss of energy =12C1C2(C1+C2) V1-V22

                             =125×10-6×5×10-62000-100025+5×10-6

                             = 5×52×10=1.25 J

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