Two identical conducting spheres A and B carry an equal charges. They are separated by a distance much larger than their diameters, and the force between them is F . A third identical conducting sphere, C , is uncharged. Sphere C is first touched to A , then to B , and then removed. As a result, the force between A and B would be equal to:

Question

Two identical conducting spheres A and B carry an equal charges. They are separated by a distance much larger than their diameters, and the force between them is F . A third identical conducting sphere, C , is uncharged. Sphere C is first touched to A , then to B , and then removed. As a result, the force between A and B would be equal to:, 3 F 4, F 2, 3 F 8, F

MARKS App · Accepted Answer

F = k q 2 r 2 when A and C are touched charge on both will be q 2 . Then when B and C are touched, q B = q 2 + q 2 = 3 q 4 F ′ = k q A q B r 2 = k × q 2 × 3 q 4 r 2 = 3 8 k q 2 r 2 = 3 8 F .

Search any question & find its solution

Looking for more such questions to practice?