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Question: Answered & Verified by Expert
Two identical conducting wires $\mathrm{A O B}$ and $\mathrm{C O D}$ are placed at right angles to each other. The wire $\mathrm{AOB}$ carries an electric current $\mathrm{I_1}$ and $\mathrm{COD}$ carries a current $\mathrm{I_2}$. The magnetic field on a point lying at a distance ' $\mathrm{d}$ ' from $\mathrm{O}$, in a direction perpendicular to the plane of the wires $\mathrm{A O B}$ and $\mathrm{C O D}$, will be given by
PhysicsMagnetic Effects of CurrentJEE MainJEE Main 2007
Options:
  • A
    $\frac{\mu_0}{2 \pi}\left(\frac{\mathrm{I}_1+\mathrm{I}_2}{d}\right)^{1 / 2}$
  • B
    $\frac{\mu_0}{2 \pi \mathrm{d}}\left(\mathrm{I}_1^2+\mathrm{I}_2^2\right)^{1 / 2}$
  • C
    $\frac{\mu_0}{2 \pi d}\left(\mathrm{I}_1+\mathrm{I}_2\right)$
  • D
    $\frac{\mu_0}{2 \pi d}\left(\mathrm{I}_1^2+\mathrm{I}_2^2\right)$
Solution:
1713 Upvotes Verified Answer
The correct answer is:
$\frac{\mu_0}{2 \pi}\left(\frac{\mathrm{I}_1+\mathrm{I}_2}{d}\right)^{1 / 2}$
$\frac{\mu_0 \mathrm{I}}{2 \pi \mathrm{d}} \sqrt{\left(\mathrm{I}_1^2+\mathrm{I}_2^2\right)}$

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