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Question: Answered & Verified by Expert
Two identical long conducting wires AOB and COD are placed at right angle to each other, with one above other such that ‘ O ’ is their common point for the two. The wires carry I1 and I2 currents, respectively. Point ‘ I ’ is lying at distance ‘ d ’ from ‘ O ’ along a direction perpendicular to the plane containing the wires. The magnetic field at the point ‘ P ’ will be:
PhysicsMagnetic Effects of CurrentNEETNEET 2014
Options:
  • A μ02πdI1I2
  • B μ02πdI1+I2
  • C μ02πdI12-I22
  • D μ02πdI12+I221/2
Solution:
1680 Upvotes Verified Answer
The correct answer is: μ02πdI12+I221/2


B due to wire 1 B1=μ0i12πdi^
B due to wire 2 B2=μ0i22πd-j^
Bnet=μ02πd i12+i22

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