Two identical satellites are moving around the earth in circular orbits at heights 3 R and R respectively where R is the radius of the Earth. The ratio of their kinetic energies is

Question

Two identical satellites are moving around the earth in circular orbits at heights 3 R and R respectively where R is the radius of the Earth. The ratio of their kinetic energies is, 2 : 1, 1 : 2, 3 : 1, 2 : 3

MARKS App · Accepted Answer

Kinetic energy of satellites in circular orbit is given as E k = G M m 2 r ⇒ E k 1 E k 2 = r 2 r 1 = R + R R + 3 R = 2 R 4 R = 1 2

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