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Two identical thin bar magnets each of length $l$ and pole strength $m$ are placed at right angles to each other with north-pole of one touching south-pole of the other, then the magnetic moment of the system is
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The correct answer is:
$\sqrt{2} \mathrm{ml}$
Here, distance between two poles $=\sqrt{2} 1$
Hence, $\mathrm{M}=\mathrm{m} \times \sqrt{2} \mathrm{l}=\sqrt{2} \mathrm{ml}$
Hence, $\mathrm{M}=\mathrm{m} \times \sqrt{2} \mathrm{l}=\sqrt{2} \mathrm{ml}$
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