Two large conducting plates of a parallel plate capacitor are given charges Q and 3 Q respectively. If the electric field in the region between the plates is E 0 , then the force of interaction between the plates is

Question

Two large conducting plates of a parallel plate capacitor are given charges Q and 3 Q respectively. If the electric field in the region between the plates is E 0 , then the force of interaction between the plates is, 3 Q E 0, 2 Q E 0 3, 3 2 Q E 0, Q E 0 2

MARKS App · Accepted Answer

The net electric field between the plates due to both the plates is E 0 = σ ε 0 = Q A ε 0 So the electric field due to each plate is E = E 0 2 = Q 2 A ε 0 So the force on one plate due to the other one is F = Q E = 3 Q × Q 2 A ε 0 = 3 Q 2 2 A ε 0 = 3 Q E 0 2

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