Search any question & find its solution
Question:
Answered & Verified by Expert
Two light rays having the same wavelength $\lambda$ in vacuum are in phase initially. Then the first ray travels a path $l_{1}$ through a medium of refractive index $n_{1}$ while the second ray travels a path of length $l_{2}$ through a medium of refractive index $n_{2}$. The two waves are then combined to observe interference. The phase difference between the two waves is
Options:
Solution:
2512 Upvotes
Verified Answer
The correct answer is:
$\frac{2 \pi}{\lambda}\left(n_{1} l_{2}-n_{2} l_{1}\right)$
Optical path for ray $1=n_{1} l_{1}$ Optical path for ray $2=n_{2} l_{2}$ Phase difference,
$$
\Delta \phi=\frac{2 \pi}{\lambda} \Delta x=\frac{2 \pi}{\lambda}\left(n_{1} l_{1}-n_{2} l_{2}\right)
$$
$$
\Delta \phi=\frac{2 \pi}{\lambda} \Delta x=\frac{2 \pi}{\lambda}\left(n_{1} l_{1}-n_{2} l_{2}\right)
$$
Looking for more such questions to practice?
Download the MARKS App - The ultimate prep app for IIT JEE & NEET with chapter-wise PYQs, revision notes, formula sheets, custom tests & much more.