Two liquids A and B are at 32 o C and 24 o C . When mixed in equal masses, the temperature of mixture is found to be 28 o C . Their specific heats are in the ratio

Question

Two liquids A and B are at 32 o C and 24 o C . When mixed in equal masses, the temperature of mixture is found to be 28 o C . Their specific heats are in the ratio, 3 : 2, 2 : 3, 1 : 1, 4 : 3

MARKS App · Accepted Answer

Let specific heats of liquids A and B are respectively S A and S B . It is given that T A = 32 o C , T B = 24 o C and T m i x = 28 o C When these liquids are mixed, then heat lost by A = heat gained by B ⇒ m S A Δ T = m S B Δ T ′ ⇒ m S A T A - T m i x = m S B T m i x - T B ⇒ S A 32 - 28 = S B 28 - 24 ⇒ S A × 4 = S B × 4 ⇒ S A : S B = 1 : 1

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